145Fermer147
squalylLe 01/06/2014 à 21:45
Operator overloading provides strong source code encryption (the time needed to figure out what a+b actually means is an exponential function of the number of types, implicit conversions, template specializations and overloaded operator versions involved).

trisotfl (désolé, mais c'est tordant)

ur evil printf("0x%08xn", x)edit: convert all yotd::dec << std::endl; statements to this: std::cout << std::hex << std::setfill('0') << std::setw(8) << x << s grin