44Fermer46
BookeldOrLe 26/01/2006 à 23:31
let p x y = fun z -> z x y ;;

let q () = 
  let x1 = fun x -> p x x in 
  let x2 = fun z -> x1 (x1 z) in 
  let x3 = fun z -> x2 (x2 z) in 
  let x4 = fun z -> x3 (x3 z) in 
  let x5 = fun z -> x4 ( x4 z) in 
    x5 (fun z -> z);;


tiens, pour vous amuser, typez ça!